(Solved by Humans)-30.0 mL of a 1.00 M Fe(NO3)2 solution was reacted with 25.0 mL of

Paper Details

1. ???30.0?mL?of?a?1.00?M?Fe(NO3)2?solution?was?reacted?with?25.0?mL?of?a?0.600?M?solution?of?K3PO4?to?produce?the?solid?Fe3(PO4)2?by?the?balanced?equation.

What is the limiting reagent? How many grams of Fe3(PO4)2 will be produced?

2. If 50 mL of a 1.00 M solution of CaCl2 solution A is diluted to 100. mL solution B and 70 mL of solution B is mixed with 45 mL of a 2.00 M solution of CaCl2 solution c to produce solution D, what is the molarity of the final solution (solution D)

3. Neutralization reaction equation, determine the volume of a 0.150 M H3PO4 solution needed to neutralize 27.0 mL of a 0.300 M Mg(OH)2 solution. Determine the grams of Mg3(PO4)2 that will be produced by neutralization reaction. Balanced equation 2H3PO4(aq)+3 Mg(OH)2(aq)>Mg3(PO4)2(s)+6H20(l)

4. Balanced molecular equation, complete ionic equation, and net ionic equation

Na3PO4(aq)+Zn(NO3)2(aq)>NaNO3(aq)+Zn3(PO4)2(s)

5. equilibrium constant?

CO(g)+H2O(g)<>CO2(g)+H2(g)

2NH3(g)<>3H2(g)+N2(g)

Scanned by CamScanner

A1

.

:

.

d

7 )

.

+

p o

(
-

h

.

P0

rk

?

A? .

'

&quot;

7

No ! B7

+ z ?[ ?

4

?L&amp; L

I

^

P?

_

&quot;

^

0

1

O

.

Scanned by CamScanner

Fq...

Solution details: